Trigonometry Test 2 is on Tuesday!

There are 14 questions, broken down as follows.

3 graphing rational functions

2 simplifying logs

3 log equations

2 exponential equations

1 inverse function

1 graphing exponential function

1 graphing log function

1 write the equation of an exponential function given certain conditions

Here are some good review questions.

  1. Solve for x: \log_5(2x)=\log_5(x+1)-1
  2. Solve for x and express your solution as a ratio of natural logs: 3^{\frac{-x}{2}}=4^{x+1}
  3. Sketch the graph of f(x)=-\ln(x-4)+2
  4. Sketch the graph of f(x)=e^{\frac{-x}{3}+1}
  5. Sketch the graph of f(x)=\frac{(x+2)^2(x+1)}{(x-4)^3(x-6)}
  6. f(x) has a horizontal asymptote at y=5. Where is the asymptote for f^{-1}(x)?
  7. f(x)=-5^x+1. Write the equation for f^{-1}(x).
  8. Solve for x and express your solution as a ratio of natural logs: 3^x+2=10.
  9. Re-write as an exponential equation: \log_{64}4=\frac{1}{3}.
  10. Sketch the graph of f(x)=\frac{6x^2+19x-7}{2x+7}

Also study quizzes 2, 3, and 4.

Calculus homework #5 due 3-23

1. When an electric current passes through two resistors with resistance r_1 and r_2, connected in parallel, the combined resistance, R, can be calculated from the equation \frac{1}{R}=\frac{1}{r_1}+\frac{1}{r_2}. Find the rate at which the combined resistance changes with respect to changes in r_1. Assume that r_2 is constant.

2. A museum has decided to sell one of its paintings and invest the proceeds. If the picture is sold between the years 2000 and 2020 and the money from the sale is invested in a bank account earning 5% interest per year compounded annually, then B(t), the balance in the year 2020, depends on the year, t, in which the painting is sold and the sale price P(t). If t is measured from the year 2000 so that 0<t<20 then B(t)=P(t)1.05^{20-t}.

a. Explain why B(t) is given by this formula.

b. Show that the formula for B(t) is equivalent to B(t)=1.05^{20} \frac{P(t)}{1.05^t}.

c. Find B'(10), given that P(10)=150,000 and P'(10)=5000.

3. Let f(v) be the gas consumption (in liters/km) of a car going at velocity v (in km/hr). In other words, f(v) tell you how many liters of gas the car uses to go one kilometer, if it is going at velocity v. You are told that f(80)=0.05 and f'(80)=0.0005.

a. Let g(v) be the distance the same car goes on one liter of gas at velocity v. What is the relationship between f(v) and g(v)? Find g(80) and g'(80).

b. Let h(v) be the gas consumption in liters per hour. In other words, h(v) tell you how many liters of gas the car uses in one hour if it is going at velocity v. What is the relationship between h(v) and f(v)? Find h(80) and h'(80).

c. How would you explain the practical meaning of the values of these functions and their derivatives to a driver who knows no calculus?

Trigonometry Homework #5 due 3-16

While in chem lab, you find a sandwich behind some beakers. You’re very hungry, having missed lunch, and are thinking about eating this sandwich that you found, but you don’t know how long it’s been there. Using a handy Geiger counter, you find that the sandwich has 98% of its carbon-14 remaining. Would you eat the sandwich? Explain your answer algebraically.